6/x^2+3x+2+8/x^2+3x-4=1

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Solution for 6/x^2+3x+2+8/x^2+3x-4=1 equation: 



6/x^2+3x+2+8/x^2+3x-4=1

We move all terms to the left:

6/x^2+3x+2+8/x^2+3x-4-(1)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

6x+6/x^2+8/x^2-3=0

We multiply all the terms by the denominator


6x*x^2-3*x^2+6+8=0

We add all the numbers together, and all the variables

-3x^2+6x*x^2+14=0

Wy multiply elements

-3x^2+6x^3+14=0

We do not support expression: x^3

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